What is the area of the trapezoid below?

Question

https://www.connexus.com/content/media/456845-3152…36 square root of three cm²44 square root of three cm²65 cm²88 cm²

Mina Herzog · Accepted Answer

The longer base is 7 + 4= 11We need the height, use the Pythagorean Thm.4² + h² = 8²16 + h² = 64h² = 48√h² = √(16 * 3)………√.N² = Nh = 4√3A= 1/2 (sum of the bases) * heightA= 1/2(11 + 7)* 4√3A = 1/2(18)* 4√3A = 9* 4√3A = 36√3 cm²

Mina Herzog · Answer

The bases are 7 & 11, so the average of the bases is 94^2 + h^2 = 8^2, so h = sqrt48 which is 4 sqrt3The area of a trapezoid is the average of the bases times the height: 9 * 4sqrt 3 = 36sqrt3The first one is the answer

Mina Herzog · Answer

The trapezoid consists of a triangle with sides 4cm and 8cm and a rectangle with one known side 7cm.rectangle : the height of the rectangle can be found using a little help from Pythagoras8² = x² + 4² –> x = 4sqrt(3) cmSo its area is: A1 = (4sqrt(3)cm)(7cm) = 28sqrt(3) cm²triangle: area is A2 = (4sqrt(3))(4cm)/2 = 8sqrt(3) cm²So answer number 1 is correct.

Mina Herzog · Answer

47, it`s always 47

Lavinia Carroll

What is the area of the trapezoid below?

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