What is the correct formula for the compound made form lead and chloride?

Question

What is the correct formula for the compound formed from lead and chloride? Is it PbCl2, Pb2Cl, PbCl, or PbCl4?

Anonymous · Accepted Answer

AExplanation:cause its easy

Anonymous · Answer

PbCl2 Explanation:Pb has a valency of 2 Cl has a valency of 1During bonding, there will be an exchange of ions as shown below:Pb^2+ + Cl^- —> PbCl2 Balance the equation by putting 2 in front of Cl-Pb^2+ + 2Cl^- —> PbCl2

Anonymous · Answer

74.1% + 25.9% = 100%we assume 100g of sample100%100g25.9% N xx 25.9g N100g - 25.9g = 74.1g Omass of N = 14gmass of O = 16g1 mole of N 14gx moles of N 25.9gx = 1.85 moles of N1 moles of O 16gx moles of O 74.1gx = 4.6 moles of ON : O = 1.85 : 4.6we share by the smallest valueN : O = 1.85 : 4.6  ||:1.85N : O = 1 : 2.4 ≈ 1 : 2NO₂ B

Anonymous · Answer

The formula for a compound made from and is .Explanation:For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  Here cation is having an oxidation state of +3 written as and anion is having an oxidation state of -3 written as . Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral .Thus formula for a compound made from and is .

Anonymous · Answer

D. If we take a sample of 100g of the given compound, we should find that it contains 74.1g of oxygen and 25.9g of nitrogen. The molar masses of oxygen and nitrogen are approximately 16.0g/mol and 14.0g/mol respectively. To find the appropriate number of moles of oxygen and nitrogen found in one mole of the given compound, we divide the mass of the sample by the molar mass of each substance.For oxygen: 74.1g/(16.0g/mol) = 4.63125 mol (round up to 5 mol)For nitrogen: 25.9g/(14.0g/mol) = 1.85 mol (round up to 2 mol)Therefore one mole of this compound contains 2 moles of nitrogen and 5 moles of oxygen.

Annalise Metz V · Answer

A compound is formed when two or more elements combine in definite proportions. In the given scenario we have carbon and hydrogen atoms.The valence electron configuration of C = 2s²2p²H = 1s¹There are 4 valence electrons in carbon; one paired (2s) and two unpaired (2p). Promotion of a 2s electron to a 2p orbital leaves 4 unpaired electrons which can combine with 4 H atoms to form a stable compound: CH4Ans: (a) CH4, because four electron pairs are shared between carbon and hydrogen.

Anonymous · Answer

Answer : The correct option is, HF, because both fluorine and hydrogen are capable of forming only one covalent bond. Explanation :Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.The covalent compound are usually formed when two non-metals react.Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.Ionic compound are usually formed when a metal reacts with a non-metal.As we known that, hydrogen and fluorine are non-metals. So, they are capable of forming only one covalent bond.Hence, the correct option is HF, because both fluorine and hydrogen are capable of forming only one covalent bond.

Lesly Cormier · Answer

I believe the answer is Ag₂O or AgO

Anonymous · Answer

It would be MgO because as stated in the question a magnesium ion has a charge of +2 and an oxygen ion has a charge of –2. The charges would cancel each other out therefore leaving each of the elements with only one of each.

Anonymous · Answer

Name : Magnesium FluorideFormula : MgF2Explanation:Give me brainliest

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What is the correct formula for the compound made form lead and chloride?

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