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Anonymous

Nov 14, 2024

What is the fifth term of the geometric sequence a1=120, a2=36, a3=10.8, a6=0.2916?

What is the fifth term in the geometric sequence where the first term is 120, the second term is 36, the third term is 10.8, and the sixth term is 0.2916?

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Anonymous

Jan 09, 2025

First we need to find the common ratio by dividing the second term by the first term. 36/120 = 3/10an = a1 * r^(n-1)n = term to find = 5a1 = first term = 120r = common ratio = 3/10now we sub and solvea5 = 120 * 3/10^(5 - 1)a5 = 120 * 3/10^4a5 = 120 * .0081a5 = 0.972 <=== fifth termor we could have just done thissince we multiply by 3/10 to find the next number...a3 = 10.810.8 * 3/10 = 3.24 <== 4th term3.24 * 3/10 = 0.972 <== fifth term
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Anonymous

Nov 18, 2024

The formula for geometric sequence is an = a1 r^(n-1) where r is the geometric factor and n is an interger. In the sequence given, r is equal to 3/10. In this case, an = 120* (3/10)^(n-1). Solving for a5, a5 = 120* (3/10)^(5-1) = 0.972
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Anonymous

Nov 27, 2024

Geometric Series PART 11. D2. D3. A4. C5. A6. D7. A8. A9. C10. A11. Chope this helps 🙂Step-by-step explanation: 100%
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Anonymous

Jan 10, 2025

R = a2/a1 = 36/120 = 0.2a5 = a1 * r^4 = 120 * 0.2^4 = 120 * 0.0016 = 0.192Hope it helps!
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