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A

Anonymous

Oct 13, 2024

What is the free-fall acceleration on planet 2?

The free-fall acceleration at the surface of planet 1 is 22 m/s². Given that the radius and mass of planet 2 are both twice those of planet 1, what is the free-fall acceleration on planet 2?

1 Answers

A
Anonymous

Jan 11, 2025

g1 = G M1/R1^2

g2 = G M2/R2^2


g2/g1 = [M2/M1] [R1/R2]^2

g2/g1 = [2 M1/M1] [R1/2 R1]^2

g2/g1 = [2] [1/4] = 1/2

g2 = g1/2 = 22/2

g2 = 11 m/s^2

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