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What is the impulse on a 3.0 {rm kg} particle that experiences the force described by the graph?

HERE IS THE FIGURE http://session.masteringphysics.com/problemAsset/1...

1 Answers

The impulse (Ft) is the area mapped out by the graph. The vertical axis is in standard units but your horizontal axis is in milliseconds (1 ms = 1E-3 sec).You have a large triangle in the positive region of the graph whose area is :A₁ = ½BH = ½((8-2)E-3)(2000) ……. (B = breadth; H = height)A₁ = +6 NsYou have two smaller triangles, in the negative region, which, when combined make a square whose area is :A₂ = LB = 2E-3(-500) A₂ = -1 NsThe net impulse on the particle is :Ft = 6 – 1 = 5 Ns... Show More

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