What is the impulse on a 3.0 {rm kg} particle that experiences the force described by the graph?
"Here is the figure illustrating the force experienced by a 3.0 kg particle: http://session.masteringphysics.com/problemAsset/1... What is the impulse exerted on the particle based on the force described in the graph?"
1 Answers
The impulse (Ft) is the area mapped out by the graph. The vertical axis is in standard units but your horizontal axis is in milliseconds (1 ms = 1E-3 sec).
You have a large triangle in the positive region of the graph whose area is :
A₁ = ½BH = ½((8-2)E-3)(2000) ……. (B = breadth; H = height)
A₁ = +6 Ns
You have two smaller triangles, in the negative region, which, when combined make a square whose area is :
A₂ = LB = 2E-3(-500)
A₂ = -1 Ns
The net impulse on the particle is :
Ft = 6 – 1 = 5 Ns
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