What is the new charge density on the outside of the sphere?

_______________________________A hollow, conducting sphere with an outer radius of 0.257 m and an inner radius of 0.203m has a uniform surface charge density of +6.31×10−6C/m^2 . A charge of -0.870uC is now introduced into the cavity inside the sphere.the new charge density on the outside of the sphere=p=6.31*10^-6 – (8.7*10^-7/4pi*0.257^2p = 6.31*10^-6 – (8.7*10^-7/0.8299) p = 6.31*10^-6 – 1.0482*10^-6p = 5.2618*10^-6 C/m^2A) The new charge density on the outside of the sphere is 5.2618*10^-6 C/m^2________________________B) The strength of the electric field just outside the sphere=E=5.2618×10−6/8,85*10^-12 =5.9455*10^-5 N/C________________________________The electric flux through a spherical surface just inside the inner surface of the sphere=-8.7*10^-7 /8,85*10^-12 C) The electric flux through a spherical surface just inside the inner surface of the sphere=-9.8305*10^4 Nm^2/C_____________________________... Show More