3x-6y=20 and. 2x-4y=3. I have three problems kind of like this one.?
I have a system of equations: 3x - 6y = 20 and 2x - 4y = 3. I would appreciate it if you could walk me through each step of solving these equations. I really want to learn how to approach problems like this. Thank you in advance for your help!
3 Answers
Here, to solve the system just multiply the first equation by 2 and the second equation by -3 ....
It is so 6x -12y = 40
-6x +12y = -9 ==> 0 = 31 ... it is not true, then there is no answer. The system has no solution.
I not sure if ur looking for x & y.
3x - 6y = 20
x - 6y = 6.67
x - y = 6.67/6
x - y = 1.11 .
x = 1.11 + y
-------------------------------
2x - 4y = 3
x - fy = 3/2
x - y = 3/8
x = 3/8+y.
x.x
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