What’s the molar mass of Au(NO3)3?
What is the molar mass of gold(III) nitrate, Au(NO3)3? I would appreciate your help. Thank you!
5 Answers
Molar mass = 382.9816 g/mol
Au Gold atomic mass 196.9665694 1 atom 51.4298 % of total mass
N Nitrogen atomic mass 14.00672 3 atoms 10.9718 % of total mass
O Oxygen atomic mass 15.99943 9 atoms 37.5984 % of total mass
196.9665694 + 14.00672*3 + 15.99943*9 = 382.9816 = molecular mass
So molar mass = 382.9816 g/mol
Dec 23, 2024
Other people have answered this correctly, but to figure it out:
1) Look at a periodic table. Find the mass of each element.
Au = 196.96
N = 14.01
O = 15.99
2) Figure out how many atoms you have of each (get this from the formula). Multiply.
Au = 1 * 196.96
N = 3 * 14.01 = 42.03
O = 9 * 15.99 = 143.91
3) Add them up.
196.96 + 42.03 + 143.91 = 382.9 g/mol
Now, that wasn’t so hard, was it?
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