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A

Anonymous

Jan 18, 2025

A basket of negligible weight hangs from a vertical spring scale of force constant 1500N/m .?

A basket of negligible weight hangs from a vertical spring scale with a force constant of 1500 N/m.

If you suddenly place a 3.00 kg adobe brick in the basket, what is the maximum distance the spring will stretch? Δl_max = ? cm. I calculated it to be 19.6 cm, but that seems to be incorrect.

Additionally, if you release the brick from a height of 1.00 m above the basket, how much will the spring stretch at its maximum elongation? Δl = ? cm.

2 Answers

A
Anonymous

Feb 04, 2025

let x metres be the vertical extension:

conservation of energy:

loss in potential energy = gain in spring p.e

=> mgx = ½kx²

=> x = 2mg/k = 2x3x(9.81)/1500 = 0.03924 m = 3.924 cm

b) conservation of energy:

mg (1+x) = ½kx²

=> 1500x² – 6gx – 6g = 0

or x² – .03924x – 0.004 = 0

solving x = [0.03924 ± 0.13243]/2 = 0.086 m = 8.6 cm

hope this helps

A
Anonymous

Nov 30, 2024

Try 1.96 cm

(1/2)kx^2=(1/2)mv^2

(1/2)mv^2=mgh

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