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Lori Robel

Feb 20, 2025

Which is the best of the following polynomial approximations to cos 2x near x=0?

Please explain how to do the problem!a) 1 + x/2b) 1 + xc) 1 - 2x + x^2d) 1 - (1/2)(x^2)e) 1 - 2x^2
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Alphonso Olson

Feb 20, 2025

The Maclaurin Series for f(x) = cos x is 1 - x^2/2! + x^4/4! - ...Replacing x with 2x, we getcos(2x) = 1 - (2x)^2/2! + (2x)^4/4! - ... = 1 - 2x^2 + 2x^4/3 - ...So, the answer is e).I hope this helps!... Show More
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