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Kelsie Sawayn

Feb 20, 2025

A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of?

A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water while a large ball requires a lot of force. The child happens to have a styrofoam ball (this way the shape of the ball will not distort when it is forced under the surface) which is being forced under the surface of the water. If the child needs to supply 635 N to totally submerge the ball, calculate the diameter of the ball. The density of water is ρw = 1.000 × 103 kg/m3, the density of styrofoam is ρfoam = 95.0 kg/m3 and the acceleration due to gravity is g = 9.81 m/s2.Please answer in m. Thank you!
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Hermina Ferry

Feb 20, 2025

The 635 N (F, the buoyancy) is the weight of the displaced water minus the weight of the ball itself:F = (ρw - ρfoam) V gV = 4/3 pi R^3 = 4/3 pi (D/2)^3 = 1/6 pi D^3SoF = (ρw - ρfoam) pi D^3 / 6 gD^3 = 6 F / ( pig(ρw - ρfoam))D = ( 6 F / ( pig(ρw - ρfoam)) )^(1/3)D = 0.515 m... Show More
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Hermina Ferry

Feb 20, 2025

With regard to your previous question on orbital energies, i gave you an equation for gravitational PEas : Ug = ( G m1 m2 ) / d , am uncertain as to its origin so best check it out for yourself.thanksdean... Show More
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