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Anonymous

Jan 14, 2025

A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of?

A child playing in a swimming pool observes that it is easy to push a small inflated ball under the water’s surface, while a larger ball requires significantly more force. The child also has a styrofoam ball, which maintains its shape when being submerged. If the child needs to exert a force of 635 N to fully submerge the styrofoam ball, calculate the diameter of the ball. Given that the density of water is ρw = 1.000 × 10³ kg/m³, the density of styrofoam is ρfoam = 95.0 kg/m³, and the acceleration due to gravity is g = 9.81 m/s², please provide your answer in meters. Thank you!

2 Answers

A
Anonymous

Nov 18, 2024

The 635 N (F, the buoyancy) is the weight of the displaced water minus the weight of the ball itself:

F = (ρw - ρfoam) V g

V = 4/3 pi R^3 = 4/3 pi (D/2)^3 = 1/6 pi D^3

So

F = (ρw - ρfoam) pi D^3 / 6 g

D^3 = 6 F / ( pig(ρw - ρfoam))

D = ( 6 F / ( pig(ρw - ρfoam)) )^(1/3)

D = 0.515 m

A
Anonymous

Dec 09, 2024

With regard to your previous question on orbital energies, i gave you an equation for gravitational PE

as : Ug = ( G m1 m2 ) / d , am uncertain as to its origin so best check it out for yourself.

thanks

dean

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