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Which substance is the reducing agent in this reaction? Cr2O72−+3HNO2+5H+→2Cr3++3NO3−+4H2OExpress your answer as a chemical formula.?

1 Answers

A reducing agent loses electrons, so on the left side of the equation N in HNO2 has an oxidation number of +3 and on the right side in NO3^- it has an oxidation number of +5, so it has lost electrons. Thus, the reducing agent would be HNO2.... Show More

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