A heat pump is used to keep a house warm at 22 degrees?
A heat pump is used to maintain a house temperature of 22 degrees Celsius.
a.) How much work is required from the pump to deliver 2500 J of heat into the house when the outdoor temperature is 0 degrees Celsius? Assume an ideal Carnot coefficient of performance (COP) given by the formula COP = T_H / (T_H - T_L).
b.) How much work is required from the pump to deliver 2500 J of heat into the house when the outdoor temperature is -15 degrees Celsius? Again, assume an ideal Carnot coefficient of performance with the same formula COP = T_H / (T_H - T_L).
2 Answers
Feb 09, 2025
For both cases, Work = Energy / COP. You stated the formula for COP that you can calculate, so why can not you do it?
Perhaps, I can see your problem now, in not converting to the temperatures to Kelvin before hand. Add 273 to each temperature reading.
The heating load is the heat to be rejected into the house being heater, QR.
The Heat Pump Heater COP, is defined by :
COP = QR / WHP
where WHP is the required Heat Pump Heater work.
For a Carnot Heat Pump Heater, you have :
COP = ( TH ) / ( TH - TL )
For part a you have :
QR = 2500 J
COP = ( TH ) / ( TH - TL ) = ( 295.2 K ) / ( 295.2 K - 273.2 K ) = 13.42 COP Units
WHP = QR / COP = 2500 J / 13.42 = 186 J <---------[ a ]-----------------
For Part b, you have :
COP = ( TH ) / (TH - TL ) = ( 295.2 K ) / ( 295.2 K - 258.2 K ) = 7.978 COP Units
WHP = QR / COP = ( 2500 J ) / ( 7.978 COP units ) = 313 J <------[ b ]-------
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