A small ball rolls around a horizontal circle at height y inside the cone shown in Figure P7.40. Find an expre?
A small ball rolls around a horizontal circle at a height ( y ) inside the cone shown in Figure P7.40. Find an expression for the ball’s speed in terms of ( y ) and ( g ) only. Consider the following parameters: ( r ) - the radius of the cone, ( h ) - the height of the cone, and ( y ) - the height at which the ball is rolling inside the cone.
2 Answers
I assume the cone is inverted so the apex is at zero height.
The two forces on the ball are its weight “mg” straight down and the normal force “N” exerted by the surface, in a direction perpendicular to the surface. The normal force will make angle theta with the horizontal circle. The component along the radius is the centripetal force causing the circular path. The force eqs are;
Ncos(theta) = mv^2/R
NSin(theta) = mg
Divide eqs to elliminate “N”;
Tan(theta) = gR/v^2
But “theta” is also the half apex angle so;
Tan(theta) = a/h
v^2 = gRh/a
The Radius is related to the distance “y” from the vertx by ratio & proportion;
R/y = a/h
y = Rh/a
Sub this in the velocity eq;
v = SqRt(gy)
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