A student slides a 0.75 kg textbook across a table, and it comes to rest after traveling 1.2m.
A student slides a 0.75 kg textbook across a table, and it comes to rest after traveling a distance of 1.2 meters. Given that the coefficient of kinetic friction between the book and the table is 0.34, please use the work-kinetic energy theorem to determine the initial speed of the book.
1 Answers
Here frictional force= m*g*coefficient of kinetic friction
= 0.75 * 9.8 * 0.34
=2.499 Newton
Now, Acceleration of the book = force/mass
=2.499/0.75
=3.332
and distance=1.2m
So using the formula V*V = u*u + 2as
V= 0 m/s, a=3.332 and s=1.2
so 0 = u*u +2* (-3.332)*1.2
therefore, u=2.83 m/s
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