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An internal explosion breaks an object, initially at rest, into two pieces, one of which has 2.1 times the mas?

An internal explosion breaks an object, initially at rest, into two pieces, one of which has 2.1 times the mass of the other.If 8500J J were released in the explosion, how much kinetic energy did each piece acquire? Express your answers using two significant figures. Enter your answers numerically separated by a comma.
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Anya Stehr

Feb 20, 2025

Let the masses are m & 2.1m, Let the respective velocities are v1 & v2 after the explosion. By the law of momentum conservation:-=>m1u1 + m2u2 = m1v1 + m2v2=>0 + 0 = mv1 + 2.1mv2=>v1 = -2.1v2 ---------------------(i)Thus ratio of KE1:KE2 = 1/2mv1^2:1/2(2.1m)v^2=>KE1/KE2 = 2.1/1 --------------(ii)But KE1 + KE2 = 8500=>2.1KE2 + KE2 = 8500=>KE2 = 2741.94 J=>KE1 = 5758.06 J... Show More
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