calculate the solubility product constant for this salt?
A 1.00-L solution saturated with calcium oxalate (CaC₂O₄) at 25°C contains 0.0061 g of CaC₂O₄. Could you please calculate the solubility product constant (Ksp) for this salt at 25°C?
2 Answers
CaC2O4 (s) ↔ Ca++ (aq) + C2O4-- (aq)
Ksp = [Ca++] [C2O4--]
The molecular mass of CaC2O4 is 128.1 g/mole so the concentration of the saturated solution is:
(0.0061 g) / (1.00 L) (128.1 g/mol) = 4.76x10^-5 M.
Since one Ca++ ion and one C2O4-- ion dissolve for each CaC2O4 that dissolves,
Ksp = [4.76x10^-5] [4.76x10^-5] = 2.27x10^-9.
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