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Can someone help me with hybridization?

Ethyl acetate, C4H8O2, is a fragrant substance used both as a solvent and as an aroma enhancer. (a) What is the hybridization at each of the carbon atoms of the molecule? (Type your answer using the format sp3d2 for sp3d2.)The carbon bound to the oxygen is hybridized. The other three carbon atoms are hybridized.(b) What is the total number of valence electrons in ethyl acetate?(c) How many of the valence electrons are used to make bonds in the molecule? (d) How many valence electrons are used to make bonds?(e) How many valence electrons remain in nonbonding pairs in the molecule?Thank you much if you can help out 🙂

6 Answers

(a) The rule for hybridization: All sigma bonds (single bonds and only one bond in double or triple bonds) and lone pairs (nonbonding pairs) are found in hybrid orbitals.Since it is impossible to draw a structural formula in the answer part, it will be difficult to explain, but I’ll try.Ethyl acetate: CH3 — C = O………………………… I………………………… O — CH2 –CH3I think you understand the structure.First C atom has 4 single (sigma) bonds. therefore its type of hybridization is sp3 (1 s and 3 p = 4)Second C atom has 2 single(sigma) and 1 double bond (one of them is sigma , the other is pi bond). Total sigma bonds : 3. Since only sigma bonds are hybridized, its type of hybridization is sp2 (1 s and 2 p = 4)Third C atom has 4 single (sigma) bonds. (one with oxygen, one with 4th C atom and 2 with H atoms). Total sigma bonds: 4 and therefore the type of hybridization is sp3.Finaly the fourth C atom is like the first one and the type of the hybridization is sp3.(b) Each C atom has 4 valence electrons (Group IV A) 4 C atoms have 16 valence electrons. Each O atom has 6 valence electrons (Group VI A) 2 O atoms have 12 valence electrons. Each H atom has 1 valence electron and total 8 H atoms have 8 valence electrons.Hence, the total number of valence electrons in ethylacetate molecule is 16 + 12 + 8 = 36(c) All valence electrons of C and H atoms are used to make bonds (16 + 8 = 24). In addition 2 electrons of each O atom are used to make bonds (each O atom has 2 bonds) Valence electrons used by O to make bonds : 4Total valence electrons used for making bonds are : 28(d) I think c and d ask the same question.(e) 28 valence electrons are used to make bonds out of 36, and 8 valence electrons (4 of each O atom) remain in nonbonding pair.Note: in the molecule there are 14 bonding pair and 4 nonbonding pair (lone pair).... Show More
your answers are correct expect for letter c. c: 26. There are 8 nonbonding e- and 2 e- used to make the pi bond so the answer is 36-10 = 26... Show More
sp2 hybridisation will reult in a bonding pair being used for a sigma bond between the two O atoms, and two lone pairs at approximately 120 degrees to each other (all planar). The unhybridised p orbital, containing one electron and perpendicular to the plane just mentioned, can overlap sideways with its neighbour on the other oxygen atom, forming a pi bond.... Show More
See ethyl acetate valence electron at http://www.curvedarrow.com/PW... Show More

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