Consider the skeletal structure of naphthalein (C10H8), the active ingredient in mothballs. How many double bonds must be added to

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Consider the skeletal structure of naphthalein (C10H8), which is the active ingredient in mothballs. How many double bonds need to be added to ensure that each carbon atom attains an octet of electrons?

Anonymous · Accepted Answer

four (4)Explanation:Naphthalein is an organic compound with formula C10H8. It is the simplest polycyclic aromatic hydrocarbon, and is a white crystalline solid with a characteristic odor that is detectable at concentrations as low as 0.08 ppm by mass. As an aromatic hydrocarbon, naphthalene's structure consists of a fused pair of benzene rings. It is best known as the main ingredient of traditional mothballs. The molecule is planar, like benzene. Unlike benzene, the carbon–carbon bonds in naphthalene are not of the same length. The bonds C1−C2, C3−C4, C5−C6 and C7−C8 are about 1.37 Å (137 pm) in length, whereas the other carbon–carbon bonds are about 1.42 Å (142 pm) long. This difference, established by X-ray diffraction is consistent with the valence bond model in naphthalene and in particular, with the theorem of cross-conjugation. This theorem would describe naphthalene as an aromatic benzene unit bonded to a diene but not extensively conjugated to it (at least in the ground state), which is consistent with two of its three resonance structures. Because of this resonance, the molecule has bilateral symmetry across the plane of the shared carbon pair, as well as across the plane that bisects bonds C2-C3 and C6-C7, and across the plane of the carbon atoms. Thus there are two sets of equivalent hydrogen atoms: the alpha positions, numbered 1, 4, 5, and 8, and the beta positions, 2, 3, 6, and 7. Two isomers are then possible for mono-substituted naphthalenes, corresponding to substitution at an alpha or beta position. Bicyclo[6.2.0]decapentaene is a structural isomer with a fused 4–8 ring system.Therefore four (4) double bonds will be added to give each carbon atom an octet structure.

Anonymous · Answer

1:Liner 2:None 3:Pentane 4:Alkene 5: Organic compounds 6: IDK 7: IDK8: Synthetic

Aylin Zboncak · Answer

- noneExplanations:- For naming hydrocarbons we use the suffix -ane, -ene and -yne. -ane is used when we have only single bonds between all carbons. -ene is used if there is any double bond between two carbons and the -yne is used if there is any triple bond between two carbons. The given name of the compound is propane. It ends at -ane and so it's an alkane and must have single bonds between all the carbons it has. So, there are zero double bonds present in .This is also clear from the below lewis dot structure of the compound.

Anonymous · Answer

0Explanation:An image of the lewis structure of the compound OF2 is shown in the image attached. A Lewis structure is a structure in which electron pairs on atoms are shown as dots. Sometimes shared electron pairs are shown by a horizontal straight line connecting the two atoms involved.OF2 has no double bonds as shown in its structure. It is a compound containing only two O-F sigma bonds and no pi-bonds.

Anonymous · Answer

2.Explanation:Kindly, find the attached image:there are 2 double bonds in this molecule:one between CH and CH.The other between Ca and O in the carbonyl group.

Anonymous · Answer

Answer : The number of double bonds present in propane is, Zero.Explanation :Lewis-dot structure : Lewis-dot structure shows the bonding between the atoms of a molecule and also shows the unpaired electrons present in the molecule.Carbon has '4' valence electrons and hydrogen has '1' valence electrons.The total number of valence electrons in = 3(4) + 8(1) = 20In the given molecule propane, there is a single bond present between the carbon-carbon atom and carbon-hydrogen atom.According to the Lewis-dot structure, the number of double bonds present in propane is, Zero.The Lewis-dot structure is shown below.

Anonymous · Answer

answer is attached below :-      answer is zero{  in 2 figures}

Gerardo Price · Answer

C2H4 is called Ethene and the dot diagram of Ethene has one bond between the carbon atoms. Each line in this diagram represents one pair of shared electrons.

Anonymous · Answer

Carbon dioxide is considered as liner molecule

Anonymous · Answer

Double bond can’t be present in HF compound due to Hydrogen elements .. it is just have one electron ..

Anonymous

Consider the skeletal structure of naphthalein (C10H8), the active ingredient in mothballs. How many double bonds must be added to

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