10 Answers
Option (d) is the correct answer.Explanation:It is known that NaCl is an ionic compound as it is formed by transfer of an electron from sodium atom to chlorine atom. Since, an ionic bond is a bond formed due to transfer or donation of an electron from one atom to another.Also, ionic compounds are soluble in polar solvents because like dissolves like.So, when NaCl is added into water then it will dissociate into ions as and . As a result, due to the opposite charges there will occur strong ion dipole attractions between these ions and water molecules.Whereas kerosene comes from petroleum (non-polar hydrocarbon) therefore, kerosene is a non-polar solvent. Hence, NaCl will not dissolve in it.Thus, we can conclude that NaCl will be more soluble in water, because water is polar and can separate the cation and anion in the lonic compound, creating very strong ion dipole attractions.
a.Explanation:At 28 degrees highest line is CaCl2. Answer a.
Explanation:Alcohols with _Low__ molecular weights are more water soluble than alcohols with _high__ molecular weights because, as a result of having fewer carbons, they have a smaller non polar component that has to be dragged into water. Whereas the case is reverse with the high molecular weight alcohols.
Explanation:Propanone is more soluble in water compared to butane due to the presence of hydrogen bonds in propanone. Hydrogen bonds are special dipole-dipole attraction in polar molecules in which hydrogen atom is directly joined to a highly electronegative atom such as oxygen, nitrogen or fluorine. Hydrogen bonds allow molecules such as propanone to be soluble in water since they can mix intimately with the water via the bond.
NaCl is more soluble in NH3 and I2 is more soluble in C7H16Explanation:Polar substances are likely to dissolve in polar solvents. For example, ionic compounds, which are very polar, are often soluble in the polar solvent water. Nonpolar substances are likely to dissolve in non-polar solvents.For example, ionic compounds are insoluble in hexane.In the above example NaCl is a polar compound made up of ions so it is soluble in polar compounds like ammonia (NH3),where as I2 is a non-polar solid so it is soluble in non-polar solvents like n-heptane(C7H16).
Propane-1,3-diol is more soluble in water than 2-methylpropan-1-ol because propane-1,3-diol can form more hydrogen bonds with water.Explanation:The structures of the two compounds are shown below.The two compounds have almost the same molecular mass (72 vs 74), so the important factor must be the number of OH groups.Thus, propane-1,3-diol is more soluble in water than 2 methyl 1 propanol because propane-1,3-diol can form more hydrogen bonds with water.A and C are wrong. The molecular masses of the two compounds are almost identical.B is wrong. Fewer hydrogen bonds would make 2-methylpropan-1-ol less soluble.
The answer to your question is:Explanation:The rank is:1) HOOCCOOH2) HOOC(CH2)5COOH 3) CH3(CH2)5COOHThe statements that are true are in bold.1) Larger compounds can form more hydrogen bonds than smaller compounds with similar structures. This is incorrect the larger the compounds, the less hydrogen bonds they can form.2) Compounds that can form more hydrogen bonds are more soluble in water. This statement is true, compounds that form hydrogens bonds can interact with water.3) Smaller compounds are generally more soluble in water than larger compounds with similar structures. This option is true because the smaller the molecules the more hydrophilic they are.
The correct option is A. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid. Explanation:An ion-dipole interaction occurs when an ionic compound is placed in a polar solvent. As salts are ionic compounds and water is a polar solvent, so the fatty acid salts will be able to form electrostatic ion-dipole interactions with the polar water molecules. These interactions will cause fatty acid salts to dissolve in water.The fatty acid is not an ionic compound and will not form the ion-dipole interactions with the water molecules. Hence, fatty acids will be less soluble in water.
When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate.When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucoseWhen comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acidExplanation:When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate. Because always a salt is more soluble in water than its acid (Solubility of propionic acid is 0,37g/mL and of sodium propionate is 1g/mL). When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose because cyclohexane is made from petroleum and its polarity is very low (cyclohexane is insoluble in water and solubility of glucose is 0,91g/mL). When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid because an acid has a medium-high solubility in water but, again, an alkane derived from petroleum has very low solubility in water (hydrochloric acid has a solubility of 0,823g/mL and ethyl chloride is insoluble in water).I hope it helps!
I think it’s A I could be wrong
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