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empirical formula for mercury and oxygen?

there are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with oxygen gas escaping into the atmosphere while leaving a residue of pure mercury. heating .6498g of one of the compounds leaves a residue of .6018 go. heating .4172 g of the other compound results in a mass loss of .016 g. how do u find the empirical formula of each compound?
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Dana Herzog

Feb 20, 2025

Atomic weights: Hg=200.6 O=16Let the first compound be called C. 0.6498gC – 0.6018gHg = 0.048g O0.6018/200.6 = 0.0030.048/16 = 0.0030.003/0.003 = 1.000The empirical formula of the first compound is HgO Let the second compound be called C.0.4172gC – 0.016gO = 0.4012g Hg0.4012/200.6 = 0.0020.016/16 = 0.001The empirical formula of the second compound is Hg2O... Show More
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Dana Herzog

Feb 20, 2025

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