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Anonymous

Nov 20, 2024

empirical formula for mercury and oxygen?

There are two binary compounds of mercury and oxygen. Heating either of them results in the decomposition of the compound, with oxygen gas escaping into the atmosphere while leaving a residue of pure mercury. When heating 0.6498 g of one of the compounds, a residue of 0.6018 g of mercury remains. In the case of the other compound, heating 0.4172 g results in a mass loss of 0.016 g. How can I determine the empirical formula of each compound?

3 Answers

Atomic weights: Hg=200.6 O=16

Let the first compound be called C.

0.6498gC – 0.6018gHg = 0.048g O

0.6018/200.6 = 0.003

0.048/16 = 0.003

0.003/0.003 = 1.000

The empirical formula of the first compound is HgO

Let the second compound be called C.

0.4172gC – 0.016gO = 0.4012g Hg

0.4012/200.6 = 0.002

0.016/16 = 0.001

The empirical formula of the second compound is Hg2O

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