Find the dimensions of a rectangle with perimeter 108 m whose area is as large as possible?
What are the dimensions of a rectangle with a perimeter of 108 meters that maximizes its area?
3 Answers
A square is the rectangle required for maximum area.
If the perimeter is 108, the sides will be 108/4 = 27m
The dimensions of a rectangle with perimeter 108 m
whose area is as large as possible?
For the rectangle to have the maximum area, the dimensions should be equal.
Let the dimensions be x
thus the perimeter will be:
2(x + x) = 108
2(2x) = 108
4x = 108
x = 27
thus for the rectangle to have a maximum area the dimensions should be 27m by 27 m
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