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Find the vertex, focus, directrix, and focal width of the parabola. x= 4y^2?

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Dr. Juanita Wolff

Feb 20, 2025

given the horizontal 4p(x − h) = (y − k)^2the vertex is at (h,k)the focus is at (h+p,k)the directrix is at x= h−pand the focal width = |4p|so x = 4y^2∴ (1/4)(x − 0) = (y − 0)^2∴ 4(1/16)(x − 0) = (y − 0)^2so the vertex is at (h,k) = (0,0)the focus is at (h+p,k) = (1/16,0)the directrix is x = h−p ⇒ x = -1/16the focal width is |4p| = 1/4... Show More
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