help please? How many grams of ethyl alcohol will result? and How many grams of ethyl alcohol will result?

Balanced equation

C2H4 + H2O → C2H5OH

1mol C2H4 reacts with 1mol H2O to produce 1mol C2H5OH

How many grams of ethylene are needed to react with 0.130 mol of H2O? I got 3.65g

0.130mol H2O will react with 0.130mol C2H4

Molar mass C2H4 = 28.05 g/mol

0.130mol = 0.130*28.05 = 3.65g Your answer correct

How many grams of ethyl alcohol will result?

0.130mol ethanol will be produced

Molar mass C2H5OH = 46.07

0.130mol = 0.130*46.07 = 6.0g

How many grams of water are needed to react with 0.361 of ethylene? 6.51g

presume 0.361 mol.

0.361mol required = 0.361*18.0153 = 6.50g Your answer correct

How many grams of ethyl alcohol will result?

0.361mol C2H54OH will be produced

0.361mol = 0.361*46.07 = 16.63g C2H5OH will be produced.

hi. i'm not sure if it incredibly is nice simply by fact it incredibly is been awhile for the reason that I took chemistry yet i will attempt my superb. the respond I have been given grow to be a million.40 9 mol NaCl / L C2H5OH. If it incredibly is appropriate right this is my paintings. If no longer, ignore with reference to the paintings, i assume. 7.eighty 3 g/.09 L = 87 g/L 87 g/L X a million mol/fifty 8.5 g(that's the molar mass of the NaCl) = a million.40 9 mol/L

balanced equation is

C2H4 + H2O -> C2H6O

so..1 mol of c2h4 reacts with 1 mole of water to result in 1 mole of C2H6O

0.130 mol of H2O reacts with 0.130 mol of C2H4 to form 0.130 mol of C2H6O

0.130 mol of C2H4 corresponds to 3.64 g of C2H4

(no of moles = gn mass/ molecular mass

so, req mass = no. of moles * molecular mass)

0.130 mol of C2H6O corresponds 5.98 grams

similarly calculate for the nxt set....

molecular mass of C2H4 = 28

molecular mass of C2H6O = 46

1 mole of ethene reacts with 1 mole of water producing 1 mole of ethanol

0.13 moles of water reacts with 0.13 moles or 0.13 x 28 = 3.64 g ethene

0.13 moles water will produce 0.13 moles or 0.13 x 46 = 5.98 g ethanol

0.361 g ethene = 0.361/28 = 0.0129 moles. 0.0129 moles water = 0.0129 x 18 = 0.0322g

or, if you meant moles, 0.361 moles water = 6.5g (you did)

0.361 moles ethene will produce 0.361 moles ethanol..... and so on