How do I prepare of HCl 37%, HCl 2% & HCl 1molar?

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Mr. Frankie Stiedemann · Accepted Answer

Actually HCl is a gas and what you buy from suppliers is concentrated HCl around 37% You should see on the label the exact concentration (maybe 37.3%) but lets say it is 37%.Therefore the first solution you don’t make it; you buy it.Let’s assume you want to prepare Vfinal ml of each solutionThen you will need Vstock ml from the 37% You can use the formula M1*V1=M2*V2 even in the % case because we are talking about the same compound so the factors by which you have to multiply/divide the % to convert to molarity are simplified;so for 2% => 37 * Vstock = 2* Vfinalthus Vstock =(2/37) * Vfinal mlSo you take a suitable volumetric cylinder or flask, put a bit of distilled water, add Vstock ml of the 37% solution, fill-up to Vfinal with distilled water and mix.For 1 molar we need to do the conversion 37% is 37 gr/ 100ml or 370 gr/ liter or 370/MW mole/lt =370/38.5= 9.61 MSo 9.61 *Vstock= 1* Vfinal=> Vstock =(1/9.61)* Vfinal ml.

Mr. Frankie Stiedemann · Answer

This Site Might Help You.RE:How do I prepare of HCl 37%, HCl 2% & HCl 1molar?

Mr. Frankie Stiedemann · Answer

Hydrochloric Acid 37

Mr. Frankie Stiedemann · Answer

To ansewr this question we must know the ” Acide(HCl) degree of purification” but now we assume it HCl 100%. soto preaper HCl 1molar:1mol HCl = 1+35.5 = 36.5 gDencity = 1.84 (for HCl)so the Volume of Acide is:V=m/D = 36.5 / 1.84 = 19.38 ccso if you mix 19.8 cc HCl (100%) + 80.2 cc Water you will preaper HCl 1 molar.HCl 37% means 37 cc HCl in 100 cc Water.and HCl 2% = 2cc HCl + 98 cc Water.we can also calculate this from N1V1=N2V2 furmula.

Mr. Frankie Stiedemann · Answer

2% is consider to 100 that said 0.02 and it is multiply amount water required in ml

Dana Herzog

How do I prepare of HCl 37%, HCl 2% & HCl 1molar?

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