How many atoms are in 1.14 moles of SO3?
How many atoms are present in 1.14 moles of sulfur trioxide (SO₃)?
6 Answers
use Avogadro constant (symbols: L, NA), also called the Avogadro number N(A)= 6.02 x 10^23 mol^-11 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules.thus, 1.14moles will contain;= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23 atoms O/1mol O]= 2.05884 x 10^24 oxygen atoms= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23 atoms O/1mol O]= 6.8628 x 10^23 sulfur atomshope this helps:-)
There are a total of 4 atoms in one molecule of SO3. So if we have 1.14 moles of SO3 then we have1.14 x 4 = 4.56 moles of atomsthen we’ll multiply by avagadro’s number:4.56 x (6.02 x 10^23) = 27.5 x 10^23 atoms = 2.75 x 10^24 atoms
Jan 31, 2025
there are Avogadro’s number of molecules per mole. Avogadro’s number is 6.02×10^23 molecules/mole or atoms/gram-atom
Therefore 1.14×6.02= 6.86 x10^23 molecules of SO3 with 4 atoms per molecule = 4×6.86×10^23 atoms=27.44 x 10^23 atoms or 2.744×10^24 atoms
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