how many grams of glucose would you have to weigh out to make 500 mls of a 0.5M solution of glucose?
1 Answers
Molar mass of glucose = 180.16 g/mol
This means that 1 mole of glucose = 180.16 g.
A 1M solution contains 1 mole per litre, that is, for glucose, 180.16 g per litre.
So, 1M glucose = 180.16 g/L
You only need 0.5M, so you divide the number of grams by 2.
(Half the amount of solute in 1 litre gives you half the molarity)
Therefore, 0.5M = 180.16 / 2 = 90.08 g/L
So you now have a 0.5M solution which has 90.08 grams glucose in 1 litre,
but you only need half a litre (500 mL).
Half a litre will contain half the quantity of glucose, which is 90.08/2 = 45.04 g.
So, to make 500 mL of a 0.5M solution of glucose, you add 45.04 g glucose
to a flask and make up the rest of the volume to a total of 500 ml with water.
This is the definition of molarity in that it is the number of moles of solute
per litre of SOLUTION, not the number of moles of solute per litre of WATER.
That is, don’t make the mistake of adding 500 mL of water to the glucose,
or the total volume will be more than 500 mL.
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