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Ben Willms

Dec 27, 2024

How many grams of li3n can be formed from 1.75 moles of li?

How many grams of Li3N can be formed from 1.75 moles of Li, assuming an excess of nitrogen? The balanced chemical equation is: 6 Li(s) + N2(g) → 2 Li3N(s). Given this information, how many grams of Li3N can be produced from 1.75 moles of Li? The possible answers are: 18.3 g Li3N, 61.0 g Li3N, 58.3 g Li3N, 20.3 g Li3N, and 15.1 g Li3N.

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Anonymous

Nov 26, 2024

20.3 gFirst, determine how many moles of Li3N you can produce from 1.75 moles of Li. Since each molecule of Li3N requires 3 atoms of Li, that means that from 1.75 moles of Li, you can only produce 1.75 / 3 = 0.5833 moles of Li3N.Now compute the molar mass of Li3NAtomic weight of Lithium = 6.941Atomic weight of Nitrogen = 14.0067Molar mass of Li3N = 3 * 6.941 + 14.0067 = 34.8297 g/molNow multiply the molar mass by the number of moles34.8297 * 0.5833 = 20.316 gOf the available 5 choices, only 20.3 g is correct.
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A
Anonymous

Dec 10, 2024

The balance chemical reaction is:6 Li(s) + N2(g) → 2 Li3N(s)We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li
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Chemistry Stoichiometry

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