How many grams of li3n can be formed from 1.75 moles of li?

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How many grams of li3n can be formed from 1.75 moles of li? assume an excess of nitrogen. 6 li(s) + n2(g) â 2 li3n(s) how many grams of li3n can be formed from 1.75 moles of li? assume an excess of nitrogen. 6 li(s) + n2(g) â 2 li3n(s) 18.3 g li3n 61.0 g li3n 58.3 g li3n 20.3 g li3n 15.1 g li3n?

Oran Armstrong · Accepted Answer

20.3 gFirst, determine how many moles of Li3N you can produce from 1.75 moles of Li. Since each molecule of Li3N requires 3 atoms of Li, that means that from 1.75 moles of Li, you can only produce 1.75 / 3 = 0.5833 moles of Li3N.Now compute the molar mass of Li3NAtomic weight of Lithium = 6.941Atomic weight of Nitrogen = 14.0067Molar mass of Li3N = 3 * 6.941 + 14.0067 = 34.8297 g/molNow multiply the molar mass by the number of moles34.8297 * 0.5833 = 20.316 gOf the available 5 choices, only 20.3 g is correct.

Oran Armstrong · Answer

The balance chemical reaction is:6 Li(s) + N2(g) → 2 Li3N(s)We use the amount of the Lithium reactant and the relations of the substances from the reaction to calculate the amount of product produced. We do as follows:1.75 mol Li ( 2 mol Li3N / 6 mol Li ) (34.83 g / mol) = 20.32 g Li

Jace Toy DDS

How many grams of li3n can be formed from 1.75 moles of li?

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