How many grams of Phosgenite can be obtained…..?
How many grams of phosgenite can be obtained from 14.5 g of PbO and 14.5 g of NaCl in the presence of excess water and CO2? The balanced equation is as follows: 2PbO + 2NaCl + H2O + CO2 = Pb2Cl2CO3 + 2NaOH. Phosgenite can be considered a mixture of two lead compounds. Which compounds are combined to form phosgenite? Please provide your answers in chemical formulas.
2 Answers
what you’re doing here is a limiting reagent question.
n(PbO) = m/M = 14.5/(207.2+16) = 0.064964mol
n(NaCl) = m/M = 14.5/(35.45+22.99) = 0.248118mol
since the ratios are 2:2, the PbO is the limiting reagent.
mol(phosgenite) = 1/2 x 0.064964 = 0.032482
mass(phosgenite) = n*M = 0.032482 x (2*207.2 + 2*35.45 + 12.01 + 3*16)
= 0.032482 x 545.31
= 17.713g (3dp)
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