How many moles of cao form when 98.60 g caco3 decompose

Question

How many moles of CaO are produced when 98.60 g of CaCO3 decomposes?

Ms. Aubrey Lockman III · Accepted Answer

The balanced reaction is:CaCO3 = CaO + CO2We are given the amount of CaCO3 to decompose when heated. Thiswill be our starting point.  98.60 g CaCO3 ( 1 mol CaCO3 / 100.09 grams CaCO3) (1 molCaO / 1 mol CaCO3 ) ( 56.08 g O2 / 1 mol CaO) =  55.25 g CaO

Anonymous · Answer

0.9851mol.                      This is the rt answer just did it

Mr. Felton McClure MD · Answer

1) Chemical equationCaCO3 ---> CaO + CO22) Molar ratios 1 mol CaCO3 : 1 mol CaO : 1 mol CO23) Number of moles of reactant: 98.60 g CaCO33.1) Calculate the molecular mass of CaCO3:40.08 g/mol + 12.00 g/mol + 3*16.00 g/mol = 100.08 g / mol3.2) Calculate thte number of moles using the formula numbe of moles = mass in grams / molecular mass=> number of moles = 98.60 g / 100.08 g / mol = 1.015 mol of CaCO34) Using the theoretical molar ratios you know 1 mole of CaCO3 produce 1 mol of each product, then with 1.015 mol of CaCO3 you will obtain 1.015 mol of CO, which rounded to 3 significant figures is 1.02 mol. 1.02 mol

Anonymous · Answer

0.9852 moles of CaOExplanation:Reaction equation for the decomposition of CaCO₃:CaCO₃ → CaO + CO₂The question asks how many moles of CaO form when 98.60g of CaCO₃ decompose.We can see from the reaction equation that for every mol of CaCO₃, one mol of CaO will be produced (molar ratio 1:1)So first we need to calculate how many moles are the 98.60g of CaCO₃:Molar Mass of CaCO₃ = molar mass Ca + molar mass C + 3 * molar mass O                                      = 40.078 + 12.011 + 3 * 15.999 = 100.086 g/molMoles of CaCO₃ = mass CaCO₃ / molar mass CaCO₃Moles of CaCO₃ = 98.60 g / 100.086 g/mol = 0.9852 moles CaCO₃As we said before for every mol of CaCO₃, one mol of CaO is produced.So the decomposition of 0.9852 moles of CaCO₃ will produce 0.9852 moles of CaO.

Anonymous · Answer

Hey I think it is going to be 0986 moles. Cuz we can see that no. of moles of CaCO3 which will decompose is equivalent to the no. of CaO . Now it's just the matter of finding the no. of moles of CaCO3 . no.of moles=mass /relative molecular mass

Anonymous · Answer

Its 0.9851 I just took it

Anonymous

How many moles of cao form when 98.60 g caco3 decompose

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