I need help with this chemistry question PLEASE!?
I need help with a chemistry question, please!
Suppose you have created a saturated solution of a solute by dissolving it in 56.0 g of water at a temperature of 20.0 °C. If the temperature is increased to 30.0 °C, how much additional solute can be added? The solubility of the solute at these temperatures is as follows: at 20.0 °C, the solubility is 37.4 g per 100 g of water, and at 30.0 °C, the solubility increases to 71.5 g per 100 g of water.
1 Answers
At 20°C you can dissolve 37.4g in 100g water
This is 56/100*37.4 = 20.9g in 56g water
At 30°C you can dissolve 71.5g in 100g water
This is 56/100*71.5 = 40.0g in 56g water
Therefore by increasing the temperature from 20°C to 30°C you can add a further 40.0 – 20.9 = 19.1g extra solute.
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