Dr. Trace Abbott I
Oct 26, 2024
If 27.0 g of MgSO4.7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
If 27.0 g of magnesium sulfate heptahydrate (MgSO4·7H2O) is thoroughly heated, what mass of anhydrous magnesium sulfate (MgSO4) will remain after the water of hydration has been eliminated?
1 Answers
MGSO4 = 120.3 G/ mol
7H20 = 126 G / mol
MGSO4.7H2O = 246.3 Grams per mole
molar mass of Anhydrous MGSO4 = 120.3
Divide 120.3 by the hydrated mass of 246.3
SO… Multiply (120.3/246.3) with the mass of sample, which is 27 G, and you get the mass of the sample without the water.
Mass of sample without water is : ~13.2G
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