If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what fraction of the water would be vaporized?
"If this same quantity of energy were transferred to 2.5 kg of water at its boiling point, what fraction of the water would be vaporized?
Quantitative Energy Problem: Energy Constants for Water (H2O): - Heat of Fusion (Melting or Freezing): 334 J/g - Heat of Vaporization (Evaporating or Condensing): 2260 J/g - Heat Capacity (c) of Solid Water: 2.1 J/g°C - Heat Capacity (c) of Liquid Water: 4.18 J/g°C
Given these constants, how much of the water would be converted to vapor if the energy is applied at the boiling point?"
1 Answers
1) First, we need to understand what we're looking for:
- We have 2.5 kg of water at its boiling point (100°C)
- We want to find what fraction will vaporize
- We need to use the heat of vaporization
2) Convert kg to grams:
2.5 kg = 2500 g
3) The heat of vaporization of water is 2260 J/g
- This means it takes 2260 Joules to vaporize 1 gram of water
4) To find what fraction vaporizes, we need:
- Let x be the mass of water that vaporizes
- Energy = mass × heat of vaporization
- Energy = x × 2260 J/g
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