Skip to main content
A

Anonymous

Feb 17, 2025

In a particular redox reaction, mno2 is oxidized to mno4– and cu2 is reduced to cu . complete and balance the equation for this

In a redox reaction, MnO₂ is oxidized to MnO₄⁻, while Cu²⁺ is reduced to Cu. Complete and balance the equation for this reaction in an acidic solution. Indicating the phases is optional.

10 Answers

A
Anonymous

Dec 19, 2024

First, formulate the half-reactions. Let's take the reaction involving Mn. Determine the oxidation number of Mn to determine the number of electrons in the reaction.For MnO₂: x + 2(-2) = 0 --> x = +4For MnO₄⁻: x + 4(-2) = -1 --> x = +7Thus,MnO₂ --> MnO₄⁻ + 3e⁻For Cu₂: 0For Cu²⁺: 2⁺Thus,Cu²⁺ + 2e⁻ --> CuNow, to eliminate the electrons, multiply the first reaction with 2 and the second half-reaction with 3. 2 MnO₂ --> 2 MnO₄⁻ + 6e⁻3Cu²⁺ + 6e⁻ --> 3 CuAdd the reactions:2 MnO₂ + 3Cu²⁺ + 6e⁻ --> 2 MnO₄⁻ + 6e⁻ + 3 CuEliminate like terms in the reactant and product side:2 MnO₂ + 3Cu²⁺ --> 2 MnO₄⁻ + 3 Cu
2H2O + MnO2 + 3Ag^+> MnO4^- + 4H^+ + 3AgExplanation:Oxidation half equation:2H2O + MnO2 > MnO4^- + 3e + 4H^+Reduction half equation:3Ag^+ + 3e > 3AgOverall redox reaction equation:2H2O + MnO2 + 3Ag^+> MnO4^- + 4H^+ + 3AgThe hydrogen ions comes from water.
A
Anonymous

Jan 27, 2025

3Sb^3+(aq) + BrO3^-(aq) + 6H^+(aq)>3Sb^5+(aq) + Br^-(aq) 3H2O(l)Explanation:When we want to balance redox reaction equations, we must ensure that the number of electrons lost in the oxidation half reaction equation is equal to the number of electrons gained in the reduction half reaction equation. After we have done this, we can now write the overall balanced reaction equation without including the number of electrons lost or gained. Hence;Oxidation half equation;3Sb^3+(aq) > 3Sb^5+(aq) +6eReduction half equation;BrO3^-(aq) + 6H^+(aq) + 6e > Br^-(aq) 3H2O(l)Overall balanced reaction equation;3Sb^3+(aq) + BrO3^-(aq) + 6H^+(aq)>3Sb^5+(aq) + Br^-(aq) 3H2O(l)
4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺Explanation:In order to balance a redox reaction, we will use the ion-electron method.Step 1: Identify both half-reactionsReduction: Ag⁺ → AgOxidation: BrO⁻ → BrO₃⁻ Step 2: Perform the mass balance adding H⁺ and H₂O where necessaryAg⁺ → Ag2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺Step 3: Perform the electrical balance adding electrons where necessary1 e⁻ + Ag⁺ → Ag2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺ + 4 e⁻Step 4: Multiply both half-reactions by numbers that secure that the number of electrons gained and lost are equal4 × (1 e⁻ + Ag⁺ → Ag)1 × (2 H₂O + BrO⁻ → BrO₃⁻ + 4 H⁺ + 4 e⁻)Step 5: Add both half-reactions4 e⁻ + 4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺ + 4 e⁻4 Ag⁺ + 2 H₂O + BrO⁻ → 4 Ag + BrO₃⁻ + 4 H⁺
A
Anonymous

Feb 21, 2025

6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺Explanation:Step 1: Write the unbalanced reaction BrO₃⁻ + Sb³⁺ ⟶ Br⁻ + Sb⁵⁺Step 2: Identify both half-reactionsReduction: BrO₃⁻ ⟶ Br⁻Oxidation: Sb³⁺ ⟶ Sb⁵⁺Step 3: Perform the mass balance, adding H⁺ and H₂O where appropriate6 H⁺ + BrO₃⁻ ⟶ Br⁻ + 3 H₂OSb³⁺ ⟶ Sb⁵⁺Step 4: Perform the charge balance, adding electrons where appropriate6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂OSb³⁺ ⟶ Sb⁵⁺ + 2 e⁻Step 5: Multiply both half-reactions by numbers that assure that the number of electrons gained and lost is the same1 × (6 H⁺ + BrO₃⁻ + 6 e⁻ ⟶ Br⁻ + 3 H₂O)3 × (Sb³⁺ ⟶ Sb⁵⁺ + 2 e⁻)Step 6: Add both half-reactions and cancel what is repeated in both sides6 H⁺ + BrO₃⁻ + 3 Sb³⁺ ⟶ Br⁻ + 3 H₂O + 3 Sb⁵⁺
A
Anonymous

Dec 10, 2024

Explanation:Hello,In this case, the undergone chemical reaction is:In such a way, the acidic redox balance turns out:Which leads to the total balanced equation as follows:Thus, as the mass of oxalic acid is not given, one could suppose a value of 1 g (which you can modify based on the actual statement) in order to compute the oxalic acid moles as shwon below:Whereby the molality results:Remember you can modify the oxalic acid mass as you desire.Best regards.
A
Anonymous

Feb 16, 2025

Cu²⁺(aq) + 3NO₂⁻(aq) ⇄ Cu⁰(aq) + 2NO₃⁻(aq) Explanation:A redox reaction is a reaction that occurs with oxidation and a reduction. The compound or the element that oxides are called reducted agent because it promotes the reduction of the other one. The compound or the element that reduces is called the oxidation agent, for the same reason. In the oxidation, the substance increases its oxidation number: it loses electrons. The opposite occurs in reduction: there is a decrease in the oxidation number and the substance gain electrons. So, the oxidation reaction is:NO₂⁻(aq) ⇄ NO₃⁻(aq) + 2e⁻And the reduction:Cu²⁺(aq) + 2e⁻ ⇄ Cu⁰(aq)Note that in the first one, the oxidation number of O is always -2, and the oxidation number of N was from +3 to +5.The balanced reaction will be:Cu²⁺(aq) + 3NO₂⁻(aq) ⇄ Cu⁰(aq) + 2NO₃⁻(aq) The number of atoms of an element must be the same on each side of the equation.
A
Anonymous

Dec 01, 2024

Reduction half reaction: Cu²⁺(aq) + 2e⁻ → Cu⁰(s).Oxidation half reaction: NO₂⁻(aq) + H₂O(l) → NO₃⁻(aq) + 2H⁺(aq) + 2e⁻.  Balanced chemical reaction: Cu²⁺(aq) + NO₂⁻(aq) + H₂O(l) → Cu(s) + NO₃⁻(aq) + 2H⁺(aq).Copper is reduced from oxidation number +2 (Cu²⁺) to oxidation number 0 (Cu) and nitrogen is oxidized from oxidation number +3 (in NO₂⁻) to oxidation number +5 (in NO₃⁻).
A
Anonymous

Feb 11, 2025

The complete and balance the equation for this reaction in acidic solution is given by:Explanation:Oxidation reaction of chromium to chromate in acidic medium:Add 4 molecules of water on the left hand side to balance the oxygen:Now balance hydrogen atoms by adding hydrogen ions on opposite to the side where water molecule are present .....[1]In last, to balance the charge on the both sides add electrons to sides where positive charge is more.Reduction reaction of silver ions to silver in acidic medium:..[2]By [1] + 6 × [2] , we will get the balance equation for this reaction in acidic solution:
Cro42agWhat is the percent for the fraction nine twentieths?1.9%2.20%3.45%4.90%

Want to answer this question?

Join our community to share your knowledge!

Related Questions

1
How many oxygen atoms are in 2.00 grams of quartz?

How many oxygen atoms are in 2.00 grams of quartz? Could someone please provide a detailed explanation of the calculatio...

3
How many moles of CO2 are produced when 5.45 mole of ethane are burned in an excess of oxygen?

How many moles of CO2 are produced when 5.45 moles of ethane (C2H6) are burned in an excess of oxygen?

2
Suppose there are two known compounds containing generic x and y. you have a 1.00g sample of each compound.

Suppose there are two known compounds containing the elements x and y, and you have a 1.00 g sample of each compound. Wh...

3
what is the hybridization of phosphorus atom in PCl3?

What is the hybridization of the phosphorus atom in PCl3? Additionally, could you please provide an explanation of the s...

4
Cual es la tendencia de los metales al formar en lances

¿Cuál es la tendencia de los metales al formar enlaces? ¿Qué rango de edad sería el adecuado para explicar esta respuest...

4
How many moles of Cu are in 1.48 × 1025 Cu atoms?

How many moles of copper (Cu) are present in 1.48 × 10²⁵ atoms of copper?

10
Together, leukocytes and platelets comprise approximately percent of total blood volume

Together, leukocytes and platelets comprise approximately a certain percentage of total blood volume. In biological ter...

2
What is the hybridization on the central atom in CH2F2 and in COF2?

What is the hybridization of the central atom in the molecules CH2F2 (difluoromethane) and COF2 (carbonyl fluoride)? Add...

4
how do you draw the energy level diagram for aluminum?

What are the steps to create an energy level diagram for aluminum? Could you provide detailed guidance on how to accurat...

3
How many moles of CuO can be produced from 0.450 mol of Cu2O in the following reaction?

How many moles of CuO can be produced from 0.450 moles of Cu2O in the following reaction: 2Cu2O + O2 → 4CuO?