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A

Anonymous

Dec 02, 2024

In the figure, sin ∠MQP = .

In the provided figure, how is the sine of angle MQP related to the cosine of angle R and the sine of angle N?

7 Answers

A
Anonymous

Nov 27, 2024

we know thatin the right triangle MNR Because --------> by complementary angles sosin ∠MQP=thereforethe answer is the option D. Cos R and Sin N
A
Anonymous

Dec 01, 2024

we know thatin the right triangle MNRBecause --------> by complementary anglessosin ∠MQP=thereforethe answer is the option D. Cos R and Sin N
we know thatin the right triangle MNRBecause --------> by complementary anglesso sin ∠MQP=thereforethe answer is the option D. Cos R and Sin N
A
Anonymous

Jan 13, 2025

Sin N  = NM/NRCos R  = NM/NRso answer is D. Cos R and Sin N
A
Anonymous

Oct 18, 2024

The easiest way to get this problem correctly is by calculating the sines and cosines of all the angles in the choices then choosing the correct choice.sin ∠MQP = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠R = sin(34) = 0.559sin ∠N = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠M = sin(90) = 1cos ∠R = cos(34) = 0.828Based on these findings, it is obvious that sin ∠MQP is equal to cos ∠R and sin ∠N.Thus, the correct choice is "d".
A
Anonymous

Oct 13, 2024

The easiest way to get this problem correctly is by calculating the sines and cosines of all the angles in the choices then choosing the correct choice.sin ∠MQP = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠R = sin(34) = 0.559sin ∠N = sin(56) = 0.829cos ∠N = cos(56) = 0.559sin ∠M = sin(90) = 1cos ∠R = cos(34) = 0.828Based on these findings, it is obvious that sin ∠MQP is equal to cos ∠R and sin ∠N.Thus, the correct choice is "cos R and sin N".

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