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Physics Help! How much work is done on the gas in the process shown in the figure?

OK ive been trying to do this one question for a bit now and i can get the answer…..How much work is done on the gas in the process shown in the figure(Figure 1) ? http://session.masteringphysics.com/problemAsset/1…Ive used the W = p(Vf – Vi) formula and got -80000 J but it says its wrong, someone want to help me out?
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Everardo Feil

Feb 20, 2025

you have forgotten that the volumes are quoted in cm^3 not m^3yet your pressures are kPa which is kN per square METRE.You ALSO need to use Pa not kPa as the pressure ie must include the 10^3 which is how many pascals there are in a kPaso the change in volume is 200 * 10 ^ -6 m^3Hence the work is 400* 10 ^ 3 * 200 * 10 ^ -6 = 80000 * 10 ^ -3 J = 80 JAnd as the question is asking for work done ON THE GAS the result must be a positive.You have compressed the gas against its pressure.... Show More
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