Sickle Cell Punnett Square help!!!!?

Question

If two individuals who are heterozygous for the hemoglobin sickle cell allele produce an offspring, what is the probability that the offspring will have full blown sickle cell anemia? (Use a Punnett Square to show your work)HOW DO YOU DO THIS??Please help I will love you forever 🙂

Lavinia Carroll · Accepted Answer

Lets say; normal gene = Ssickle cell gene =sSo a heterozygous person = SsPunnett square for offspring between two heterozygous people : | S | s | ——+——–+———S | SS | Ss |——+——–+———-s | Ss | ss | —————————-So from this you can see that 1/4 (25%) gets ss, i.e. 25% have full blown sickle cell anemia50% will be heterozygous and the remaining 25% will be normal

Lavinia Carroll · Answer

Sickle Cell Anemia Punnett Square

Lavinia Carroll · Answer

Sickle Cell Punnett Square

Lavinia Carroll · Answer

This Site Might Help You.RE:Sickle Cell Punnett Square help!!!!?If two individuals who are heterozygous for the hemoglobin sickle cell allele produce an offspring, what is the probability that the offspring will have full blown sickle cell anemia? (Use a Punnett Square to show your work)HOW DO YOU DO THIS??Please help I will love you forever 🙂

Lavinia Carroll · Answer

That is true for same size populations. To know the expected values of incidence, that are 1/12 for Carriers and 1/500 for infected (http://www.cdc.gov/ncbddd/sicklecell/data.html), you also need to account the following formula: F(SS)+2*F(Ss)+F(ss)=1, so solving it with the real incidence you have F(SS)+1/12+1/500=1, this means that you have in reality the following probability for the general population: AA = 91,5%, Ss or sS = 8,3% and finally ss = 0,2%, and those are the probabilities that really matter…

Lavinia Carroll · Answer

…X^a X X XX^a XX Y X^aY XY if a male has it the y is recessive and will not hide the defect a female will only have it if both genes have the defect. if she has only one she is a carrrier

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Sickle Cell Punnett Square help!!!!?

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