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Anonymous

Feb 03, 2025

Sodium hydroxide, naoh, is a strong base that is used in industrial synthesis and processes such as making paper. what is the mass

What is the mass of 2.80 × 10^22 molecules of sodium hydroxide (NaOH), a strong base commonly used in industrial processes like paper manufacturing? The molar mass of NaOH is 40.0 g/mol.

10 Answers

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Anonymous

Jan 28, 2025

1.86 gExplanation:We must convert formula units of NaOH to moles and then to mass of NaOH.Step 1. Convert molecules to moles Step 2. Convert moles to grams
Mass of  molecules of NaOH = 1.86 gExplanation: Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by .Avogadro constant:-So,  molecules of NaOH are present in 1 mole of NaOHGiven, Molar mass of NaOH = 40.0 g/molThis means, mass of 1 mole of NaOH = 40 gSo,  molecules of NaOH weighs 40 g 1  molecule of NaOH weighs g  molecules of NaOH weighs gMass of  molecules of NaOH = 1.86 g
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Anonymous

Feb 06, 2025

                  Mass of NaOH =  1.594 gSolution:Data Given:                  Number of Molecules  =  2.40 × 10²²                  M.Mass of NaOH  =  40.0 g.mol⁻¹                  Mass of NaOH  =  ?Step 1: Calculate Moles of NaOH;   Moles  =  Number of Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹Putting value,   Moles  =   2.40 × 10²² Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹                    Moles  =  0.04 molStep 2: Calculate Mass of NaOH;                    Moles  =  Mass ÷ M.Mass Solving for Mass,                    Mass  =  Moles × M.Mass Putting values,                    Mass  =  0.04 mol × 40.0 g.mol⁻¹                    Mass  =  1.594 g
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Anonymous

Jan 15, 2025

1.46 gExplanation:For this exercise we need the Avogadro’s number that represents the number of molecules that has a mole of a substance and is value is 6.022x10^23. That is to say that 1 mole of NAOH has  6.022x10^23 molecules and by a rule of three we have:1 mole NaOH ----------- 6.022x10^23 molecules          X             ----------- 2.20x10^22 moleculesX = 0.0365 moles NaOHThen, 2.20x10^22 molecules of NaOH represent 0.0365 moles of NaOH.To find the mass we use another rule of three with the NaOH molar mass:1 mole NaOH             ------ 40.0 g 0.0365 moles NaOH ------ XX= 1.46 gSo, 0.0365 moles of NaOH have a mass of 1.46 g or 2.20 ×10^22 molecules of NaOH have a mass of 1.46 g
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Anonymous

Jan 31, 2025

1.792 gExplanation:We are given;Formula units of NaOH as 2.70 ×10^22 Molar mass of NaOH as 40.0 g/molWe are required to determine the mass of NaOH in the given formula units;Step 1: Determine the number of moles of NaOHWe need to know that 1 mole of a compound contains formula units equivalent to the Avogadro's number, 6.022 × 10^23.Therefore;1 mole of NaOH = 6.022 × 10^23 formula units Thus;Moles of NaOH = 2.70 ×10^22 ÷  6.022 × 10^23 formula units/mol                           = 0.0448 moles      Step 2: Determine the mass of NaOH Moles = mass ÷ Molar mass Therefore,Mass = Moles × Molar mass         = 0.0448 moles × 40.0 g/mol         = 1.792 gThus, the mass of 2.70 × 10^22 formula units of NaOH is 1.792 g
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Anonymous

Jan 18, 2025

1.926 g of NaOHExplanation:Concept tested: Mole and Avogadro's number We need to know that , 1 mole of a compound contains number of molecules equivalent to the Avogadro's number.Th Avogadro's number is 6.022 × 10^23 Therefore;1 mole of a compound = 6.022 × 10^23 moleculesIn this case; Our compound is NaOHTherefore;1 mole of NaOH contains 6.022 × 10^23 molecules But; Molar mass of NaOH is 40.0 g/mol Therefore;40.0 g of NaOH contains 6.022 × 10^23 molecules With this we can calculate the mass of 2.90 × 10^22 molecules Mass of a compound = (number of molecules ÷ Avogadro's constant) × molar massTherefore;Mass of NaOH =(2.90 × 10^22 molecules ÷ 6.022 × 10^23 molecules)40g                         = 1.9263 g                         = 1.926 g NaOHThus, the mass of NaOH is 1.926 g
a. 3,6x10⁻⁴ molesb. 1,096Mc. 1,53 g of NaOHExplanation:a. Theobromine has a molar mass of:C: 12,01×7= 84,07 g/molH: 1,01×8= 8,08 g/molN: 14×4= 56,04 g/molO: 16×2= 32 g/mol84,07 g/mol + 8,08 g/mol + 56 g/mol + 32 g/mol = 180,15g/mol. Thus, in 0,064g of theobromine are: = 3,6x10⁻⁴ moles -two significant figures-b. Molar mass of H₂SO₄ is 98,079 g/mol.151,1g are: = 1,54 moles of H₂SO₄As molarity is moles of solute per liters of solution, molarity is:1,54 moles of H₂SO₄ / 1,405L = 1,096 Mc. 2,30x10²² molecules of NaOH are:2,30x10²²molecules × (1mol/6,022x10²³molecules) = 0,0382 moles of NaOHAs molar mass of NaOH is 40,04g/mol: = 1,53 g of NaOHI hope it helps!
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Anonymous

Jan 16, 2025

Answer : Mass would be = 1.859 g for NaOHExplanation :  We have got  molecules of NaOH,so we get, g of NaOH/molOn solving we get, answer as 1.859 gHence the g of NaOH will be 1.86.
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Anonymous

Feb 22, 2025

Avagadros number/ constant states that there are 6.022 x 10²³ units making up 1 mol of any substance. In NaOH - there are 6.022 x 10²³ NaOH molecules in 1 mol of NaOHMass of 1 mol of NaOH - 40 gtherefore 6.022 x 10²³ molecules weigh - 40 gThen 2.60 x 10²² molecules - 40 x  2.60 x 10²² / (6.022 x 10²³ )    mass is then - 1.73 g 
F
Fannie Skiles

Feb 21, 2025

Molar mass NaOH = 40.0 g/mol40.0 g 6.02x10²³ molecules?? g 2.40x10²² molecules2.40x10²² x ( 40.0 ) / 6.02x10²³ =9.6x10²³ / 6.02x10²³ => 1.594 ghope this helps!

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