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Alize Kuhn

Feb 20, 2025

Solution of an unknown solute in cyclohexane. Freezing-point, Find molality?

Assume that you have a solution of an unknown solute in cyclohexane. If the solution has a freezing-point depression of 9.50Celcius, what is the molality of this solution? (The molal freezing-point constant of cyclohexane is 20.2 C/m)Freezing Point: 9.50Moles: ? - you need the amt of grams or have the known molar mass>?Molality: ? - you need the amt of solution - moles of solute / kg of solvent>?

5 Answers

The equation for freezing point depression isdelta T = KcmFor your problem delta T = 9.5; K = 20.2 and you need to solve for m, the molality. So, m = deltaT/K = 9.5/20.2 = 0.47 molal.... Show More
For the best answers, search on this site https://smarturl.im/aDDT6You must you the melting point depression equation: delta T = ikm i = van't off factor (excuse my spelling) assume this is 1 k = freezing point depression constant (for cyclohexane in this case, you should be given this value) m = molality of the solution = moles of unknown solute / kg of solvent (.0502kg) Using that equation, you can determine the molality of the solution. Since, molality of the solution = moles of unknown solute / kg of solvent; molality = (grams solute/molar mass solute) / (kg of solvent) This can be done because molar mass = grams/mole ----> moles = grams/(molar mass) Since all variables are known except molar mass, you can calculate the molar mass of the unknown substance.... Show More
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