Suppose a child drives a bumper car head on into the side rail, which exerts a force of 2400 N

Question

Suppose a child drives a bumper car head on into the side rail, which exerts a force of 2400 N on the car for 0.500 s. (Assume the initial velocity is in the positive direction.)(a)What impulse (in kg · m/s) is imparted by this force? (Indicate the direction with the sign of your answer.)Incorrect: Your answer is incorrect. kg · m/s (b)Find the final velocity (in m/s) of the bumper car if its initial velocity was 2.90 m/s and the car plus driver have a mass of 200 kg. You may neglect friction between the car and floor. (Indicate the direction with the sign of your answer.) m/s

Dr. Karlee Tillman · Accepted Answer

As the bumper car hits the side rail, its velocity will decrease. This means the force is negative. There are two equations for impulse.Eq#1, Impulse = Force * timeEq#2, Impulse = Mass * Change of velocityThis is the change of momentum.Impulse = -2400 * 0.5 = -1200 kg * m/s(b) Find the final velocity (in m/s) of the bumper car if its initial velocity was 2.90 m/s and the car plus driver have a mass of 200 kg. You may neglect friction between the car and floor. (Indicate the direction with the sign of your answer.) m/sThe first step is to determine the acceleration.-2400 = 200 * a a = -12 m/s^2Let’s use the following equation to determine the final velocity. vf = vi + a * tvf = 2.90 + -12 * 0.5 = -3.1 m/sThe negative sign means the bumper car is moving away from the side rail after the collision. I hope this is helpful for you.

Alize Kuhn

Suppose a child drives a bumper car head on into the side rail, which exerts a force of 2400 N

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