The bolts on the cylinder head of an engine require tightening to a torque of 86 m·N. If a wrench is L = 30 cm?
The bolts on the cylinder head of an engine need to be tightened to a torque of 86 N·m. Given that the wrench used is 30 cm long:
- What force, applied perpendicularly to the wrench at its end, must the mechanic exert? (Answer in Newtons, N)
- If the six-sided bolt head has a diameter of 15 mm, estimate the force applied near each of the six contact points by the socket wrench. (Answer in Newtons, N)
2 Answers
Torque = force * arm
Get consistent units
86 nm = F 0.30 m
F = 286.67 N
1/6 of 86 = 14.33 N*m
T = F*L
14.33 = F * 0.015 m
F = 955.33 N (At least I think that is what the question asks)
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