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Brandyn Moore PhD

Feb 20, 2025

The sum of 3 consecutive integral numbers is 117. Find the numbers.?

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7 Answers

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Abbie Toy

Feb 20, 2025

I think you mean Consecutive integers (integrals are calculus material) So:x + (x+1) + (x+2) = 1173x + 3 = 1173x = 114x = 38so, 38, 39, 40... Show More
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Abbie Toy

Feb 20, 2025

x+(x+1)(x+2)=117 x+x+1+x+2=1173x + 3 = 117 3x = 114 x = 3838+1 = 3938+2 = 40Check 38+39+40 = 117so three consecutive integral numbers are 38 ,39 and 40... Show More
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Abbie Toy

Feb 20, 2025

Let the three consecutive numbers be n-1, n, n+1 then their sum is 3n i.e. 3n=117 therefore n=39 and the three numbers are 38, 39,40... Show More
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Abbie Toy

Feb 20, 2025

a+b+c=117 b=a+1c=a+2a+a+1+a+2=117Therefore: 3a=117-3=114 . So a=38The numbers are: 38, 39 and 40.... Show More
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Abbie Toy

Feb 20, 2025

n + (n+1) + (n + 2) = 1173n + 3 = 1173n = 114n = 38so 38, 39, 40... Show More
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