Two boxes of fruit on a frictionless horizontal surface are connected by a light string as in the figure below, where m1 = 16 kg and m2 = 28?

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Two boxes of fruit on a frictionless horizontal surface are connected by a light string as in the figure below, where m1 = 16 kg and m2 = 28 kg. A force of F = 76 N is applied to the 28-kg block.https://www.webassign.net/sercp9/4-p-069-alt.gif (a) Determine the acceleration of each block and the tension in the string.1.) acceleration of m1 __?__m/s22.) acceleration of m2 __?__m/s23.) tension in the string __?__N(b) Repeat the problem for the case where the coefficient of kinetic friction between each block and the surface is 0.10.1.) acceleration of m1 __?__m/s2 2.) acceleration of m2 __?__m/s23.) tension in the string __?__N

Bernhard White · Accepted Answer

a) Both accelerate at the same rate.Acceleration = (force/ mass) = 76/(16 + 28) = 1.73m/sec^2.Tension in connecting string = (mass x acceleration) = (16 x 1.73) = 27.68N.b) Normal force = (16 + 28) x g = 44 x 9.8 = 431.2N.Friction force = (431.2 x 0.1) = 43.12N. total. Net accelerating force = (76 – 43.12) = 32.88N.Both will still accelerate at the same rate.Acceleration = (force/ mass) = 32.88/(28 + 16) = 0.75m/sec^2.Normal force of m1 alone = (16 x g) = 156.8N.Friction component of m1 alone = (156.8 x 0.1) = 15.68N.Tension due to acceleration alone, no friction = (mass x acceleration) = 16 x 0.75 = 12N.Add to that the friction force, = total tension of (12 + 15.68) = 27.68N. in the string.

Mr. Ellis Hintz

Two boxes of fruit on a frictionless horizontal surface are connected by a light string as in the figure below, where m1 = 16 kg and m2 = 28?

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