Susanna Towne
Nov 21, 2024
1)Calculate [OH^-] for 1.8×10^−3 M Sr(OH)2.?
1) Calculate the concentration of hydroxide ions, [OH⁻], for a 1.8 × 10⁻³ M solution of Sr(OH)₂.
2) Calculate the pH for a 1.8 × 10⁻³ M solution of Sr(OH)₂.
3) Calculate the concentration of hydroxide ions, [OH⁻], for 2.190 g of LiOH dissolved in 230.0 mL of solution.
4) Calculate the pH for 2.190 g of LiOH in 230.0 mL of solution.
2 Answers
[OH-] = 2 x 1.8 x 10^-3 = 0.0036 M
pOH = 2.4
pH = 14 - 2.4 = 11.6
moles LiOH = 2.190 g/ 23.948 g/mol=0.09145
[OH-]= 0.09145 / 0.2300 L=0.3976 M
pOH = 0.4005
pH = 14 - 0.4005 =13.60
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