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What is the net force exerted by these two charges on a third charge?

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is|F|=K( |QQ'| /d^2)where K=8.854 x 10^-12 C^2/(Nxm^2) is the permittivity of free space.Consider two point charges located on the x axis: one charge, Q1 = -12.0 nC , is located at x1 = -1.705m ; the second charge, Q2 = 36.5 nC, is at the origin (x=0.0000). What is the net force exerted by these two charges on a third charge Q3 = 55.0 nC placed between Q1 and Q2 at x3 = -1.155 m?Your answer may be positive or negative, depending on the direction of the force.Force on Q3= NAnd if you could please explain how to do this problem, I would very much appreciate it! Thank You!

1 Answers

Since Q1 is negative and to the left of Q3 the force will be to the leftSince Q2 is positive and to the right of Q3 the the force will also be to the leftTherefore you can add the forces together (with left being negative)Now we have F = -kQ1Q3/r13^2 - kQ2Q3/r23^2= -9.0x10^912x10^-955x10^-9/(1.705 - 1.155)^2 - 9.0x10^936.5x10^-955x10^-9/1.155^2= -3.32x10^-5N... Show More

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