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Dr. Frankie Medhurst
Feb 20, 2025
What is the partial pressure of Cl2 in the equilibrium mixture?
At 100C Kc = 0.078 for the reactionSO2Cl2 (g) (equilibrium sign) SO2 (g) + Cl2 (g)In an equilibrium mixture of the three gases, the concentrations of SO2Cl2 and SO2 are 0.107 M and 5.3×10−2 M, respectively.
1 Answers
T
Tiara Rutherford
Feb 20, 2025
Kc = [SO2][Cl2]/[SO2Cl2] = 0.078[Cl2] = (0.078)(0.107)/(5.3x10^-2) = 0.16 to two significant figures0.107 + 0.053 + 0.16 = 0.32 total moles in 1 L.0.16/0.32 = 0.5 mole fraction Cl2PV = nRT; P = nRT/V; T = 373C; R = 0.082 L-atm/mol-KP = (0.32)((0.082)(373)/(1) = 9.8 atm total pressure9.8atm x 0.5 = 4.9 atm partial pressure Cl2... Show More
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