What is the percent ionization for a weak acid HX that is 0.40 M? Ka = 4.0 × 10 −7 . 1. 0.10% 2. 2.0% 3. 0.050?
What is the percent ionization of the weak acid HX at a concentration of 0.40 M, given that its dissociation constant (Ka) is 4.0 × 10⁻⁷? The possible answers are: 1. 0.10% 2. 2.0% 3. 0.050%
1 Answers
Jan 24, 2025
Equation:
Ka = [H+]*[X-] / [HX]
[H+] = [OH-] and [HX] = 0.40M
4.0*10^-7 = [H+]² / 0.4
[H+]² = (4.0*10^-7)*0.4
[H+]² = 1.6*10^-7
[H+] = 4*10^-4
% dissociation = (4*10^*4)/ 0.40*100 = 0.1% dissociated.
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