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What is the percent ionization for a weak acid HX that is 0.40 M? Ka = 4.0 × 10 −7 . 1. 0.10% 2. 2.0% 3. 0.050?

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Tiara Rutherford

Feb 20, 2025

Equation:Ka = [H+]*[X-] / [HX] [H+] = [OH-] and [HX] = 0.40M 4.0*10^-7 = [H+]² / 0.4[H+]² = (4.0*10^-7)*0.4 [H+]² = 1.6*10^-7[H+] = 4*10^-4% dissociation = (4*10^*4)/ 0.40*100 = 0.1% dissociated.... Show More
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