projectile motion homework?

Question

A rescue pilot needs to drop a survival kit while flying at an altitude of 2,000.0 meters with a forward velocity of 100.0 m/s. Assuming air resistance is negligible, how far ahead of the starving explorer's drop zone should the pilot release the package?

Anonymous · Accepted Answer

A rescue pilot drops a survival kit while her plane is flying at an altitude of 2000.0 m with a forward velocity of 100.0 m/s. If air friction is disregarded, how far in advance of the starving explorer’s drop zone should she release the package?

The equation for a falling object

Distance = (Initial velocity * time) + (½ * 9.8 * time^2)

Distance = 2000.0 m

Initial velocity = 0 m/s

2000.0 = (0 * time) + (4.9 * time^2)

2000.0 = 4.9 * t^2

t = 20.2 seconds

As the survival kit drops vertically for 20.2 seconds, it moves horizontally for 20.2 seconds at a velocity of 100.0 m/s.

Horizontal distance = 100.0 m/s * 20.2 seconds = 2020 meters

As the survival kit drops for 20.2 seconds, it moves horizontally 2020 meters.

How far in advance of the starving explorer’s drop zone should she release the package? 2020 meters

Anonymous · Answer

Need to figure out how long it would take for the object to fall straight down from 2000 m with 0 initial velocity and only gravity affecting it.
Then, use that time and the 100 m/s to figure out the horizontal distance it will travel during the fall.

Anonymous · Answer

Velocity Kit Plane

Anonymous · Answer

Get Survival Things You Lost!

Anonymous · Answer

When the package is released it will continue for 2,019 meters.  So drop it that far from the target.
Easy equation.  Given
H = 2,000 m
Vo = 100 m/s
g = 9.81 m/s^2
R = Vo * SQRT { [2H] / g }
R = (100 m/s) * SQRT { [ 2 * (2,000 m) ] / (9.81 m/s^2) }
R = (100 m/s) * SQRT { [ 4,000 m ] / (9.81 m/s^2) }
R = (100 m/s) * SQRT { 407.7 m^2/s^2 }
R = (100 m/s) * (20.2 m/s)
R = 2,019 m

Anonymous · Answer

I can't really remember how to do this, but you have to use this knematic equation:  vf^2 = vi^2 + 2advf (final velocity) = 0vi (initial velocity) = 100 a = 9.8 (acceleration due to gravity)d = ?

Dr. Hope Daugherty II

projectile motion homework?

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