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What is the probability that Bo, Colleen, Jeff and Rohini win the first, second, third and fourth prizes, respectively (in that order),

What is the probability that Bo, Colleen, Jeff, and Rohini win the first, second, third, and fourth prizes, respectively, in that specific order? The answer is 1 in 4,669,920.

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Anonymous

Jan 09, 2025

1/4669920Step-by-step explanation:First if all, when repetition is mot allowed, we use Permutation to get the number of possible outcomes as follows;P(n, r) = n!/(n - r)! Now, the order is important since the first, second, third and fourth prizes are different.Thus, we need to define the Permutation.We need to select 4 winners of the 48 people. Thus, n = 48 and r = 4Thus; P(48,4) = 48!/(48 - 4)!P(48,4) = 4669920Now, probability is the number of favourable outcomes divided by number of possible outcomesThus, Probability = 1/4669920
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