What is the volume of 1.9 moles of chlorine gas (Cl₂) at standard temperature and pressure (STP)?

Options:
- 12 L
- 22.4 L
- 43 L
- 81 L

Question

What is the volume of 1.9 moles of chlorine gas (Cl₂) at standard temperature and pressure (STP)? 
Options:
- 12 L
- 22.4 L
- 43 L
- 81 L

Anonymous · Accepted Answer

Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol = 42. 6 L. 43 L

Anonymous · Answer

Answer : The volume of chlorine gas is, 42.56 LSolution : Given,Moles of chlorine gas = 1.9 molesAs we know that,At STP, 1 mole contains 22.4 L volume of gasAs, 1 mole of chlorine gas contains 22.4 L volume of chlorine gasSo, 1.9 moles of chlorine gas contains volume of chlorine gasTherefore, the volume of chlorine gas is, 42.56 L

Rylan Hane IV · Answer

Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/molThe answer is 43 L if I am correct.

Anonymous · Answer

Hello!For this exercise you have to use the Ideal Gas Law Equation, as follow:PV= nRTWhere:P= pressure ( in this example, atmosphere (atm) is the pressure unit)V= volume (which is the value you want to calculate)n= Mol (as reference to the mass of the gas Cl2)R = Ideal Gas Constant (for this example is a number 0.0821 atm*L/mol*K)T= Temperature in Kelvin (K)So, for find the value of the volume, you just have to replace the values given in the equation as follow:P= 1.3 atm V = you don't know, is what you want to know.n= 1.9 molR =0.0821 atmL/molKT =298 KRemember, never forget to put the units, because teacher can get down your score if you don't do it. So, back with the values to the equation:13atm * V = 1.9mol * 0.0821 atmL/molK * 298KThen, we have to solve the equation to find V value, so we has to send 1.3 atm to divide in the other side of the equation:V = (1.9mol * 0.0821 atmL/molK * 298K)/ 1.3 atm V = 35.76 LAnd, that's it! I hope this help you a lot, and good luck.

Anonymous · Answer

Hello!The answer is:The correct option is option C.Why?To calculate the volume of the gas sample, we need to use the Ideal Gas Law, this equation is used to relate the pressure, the volume, the mass and the temperature of a gas, so, we can isolate the volume from it.The Ideal Gas Law equation is equal to:Where,P is the pressure (in atm)V is the volume (in liter)n is the mass of the gass (in mole)T is the temperature of the gass (absolute temperature)So, from the statement we know that:Then, substituting and calculating we have:Now, rounding to the nearest whol number we have that the volume is equal to 36 L.Hence, the correct option is option C.Have a nice day!

Anonymous

What is the volume of 1.9 moles of chlorine gas (cl2) at standard temperature and pressure (stp)?

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